2[w-(4w+5)+3]=2(W+2)

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Solution for 2[w-(4w+5)+3]=2(W+2) equation:


Simplifying
2[w + -1(4w + 5) + 3] = 2(W + 2)

Reorder the terms:
2[w + -1(5 + 4w) + 3] = 2(W + 2)
2[w + (5 * -1 + 4w * -1) + 3] = 2(W + 2)
2[w + (-5 + -4w) + 3] = 2(W + 2)

Reorder the terms:
2[-5 + 3 + w + -4w] = 2(W + 2)

Combine like terms: -5 + 3 = -2
2[-2 + w + -4w] = 2(W + 2)

Combine like terms: w + -4w = -3w
2[-2 + -3w] = 2(W + 2)
[-2 * 2 + -3w * 2] = 2(W + 2)
[-4 + -6w] = 2(W + 2)

Reorder the terms:
-4 + -6w = 2(2 + W)
-4 + -6w = (2 * 2 + W * 2)
-4 + -6w = (4 + 2W)

Solving
-4 + -6w = 4 + 2W

Solving for variable 'w'.

Move all terms containing w to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + -6w = 4 + 4 + 2W

Combine like terms: -4 + 4 = 0
0 + -6w = 4 + 4 + 2W
-6w = 4 + 4 + 2W

Combine like terms: 4 + 4 = 8
-6w = 8 + 2W

Divide each side by '-6'.
w = -1.333333333 + -0.3333333333W

Simplifying
w = -1.333333333 + -0.3333333333W

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